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x^2-3.85x-3.5=0
a = 1; b = -3.85; c = -3.5;
Δ = b2-4ac
Δ = -3.852-4·1·(-3.5)
Δ = 28.8225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.85)-\sqrt{28.8225}}{2*1}=\frac{3.85-\sqrt{28.8225}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.85)+\sqrt{28.8225}}{2*1}=\frac{3.85+\sqrt{28.8225}}{2} $
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